The Taylor Series of the Exponential Function
Sorry for the lack of a post yesterday, but I was really tired after this weekend.
So what functions might we try finding a power series expansion for? Polynomials would be boring, because they already are power series that cut off after a finite number of terms. What other interesting functions do we have?
Well, one that’s particularly nice is the exponential function . We know that this function is its own derivative, and so it has infinitely many derivatives. In particular,
,
,
, …,
, and so on.
So we can construct the Taylor series at . The coefficient formula tells us
which gives us the series
We use the ratio test to calculate the radius of convergence. We calculate
Thus the series converges absolutely no matter what value we pick for . The radius of convergence is thus infinite, and the series converges everywhere.
But does this series converge back to the exponential function? Taylor’s Theorem tells us that
where there is some between
and
so that
.
Now the derivative of is
again, and
takes only positive values. And so we know that
is everywhere increasing. What does this mean? Well, if
then
, and so
. On the other hand if
then
, and so
. Either way, we have some uniform bound
on
no matter what the
are.
So now we know . And it’s not too hard to see (though I can’t seem to find it in my archives) that
grows much faster than
for any fixed
. Basically, the idea is that each time you’re multiplying by
, which eventually gets less than and stays less than one. The upshot is that the remainder term
must converge to
for any fixed
, and so the series indeed converges to the function
.

Is there a typo in the penultimate line? (gets less than and stays less than 1)
You’re right, sorry.
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