The Integral Mean Value Theorem
We have an analogue of the integral mean value theorem that holds not just for single integrals, not just for multiple integrals, but for integrals over any measure space.
If is an essentially bounded measurable function with a.e. for some real numbers and , and if is any integrable function, then there is some real number with so that
Actually, this is a statement about finite measure spaces; the function is here so that the indefinite integral of will give us a finite measure on the measurable space to replace the (possibly non-finite) measure . This explains the in the multivariable case, which wasn’t necessary when we were just integrating over a finite interval in the one-variable case.
Okay, we know that a.e., and so a.e. as well. This tells us that is integrable. And thus we conclude
Now either the integral of is zero or it’s not. If it’s zero, then is zero a.e., and so is , and our assertion follows for any we like. On the other hand, if it’s not we can divide through to find
this term in the middle is our .
unapologetic.wordpress.com’s done it once again. Amazing article.
Comment by Weston Montes | June 15, 2010 |
Hi,
That’s great: I was exactly looking for that result somewhere (googling ‘mean value theorem measure’, you came up second – I am rarely so lucky…). Do you know a reference (text book/article) that I could refer to to mention this result?
Thanks a lot,
Armando
Comment by Armando Sano | September 8, 2010 |
I believe it shows up in Halmos’ Measure Theory.
Comment by John Armstrong | September 8, 2010 |
Perfect, there it is, thanks again
Armando
Comment by Armando Sano | September 8, 2010 |
No problem. Remember to tell your friends where to look đ
Comment by John Armstrong | September 8, 2010 |