## Absolute Continuity I

We’ve shown that indefinite integrals are absolutely continuous, but today we’re going to revise and extend this notion. But first, to review: we’ve said that a set function defined on the measurable sets of a measure space is absolutely continuous if for every there is a so that implies that .

But now I want to change this definition. Given a measurable space and two signed measures and defined on we say that is absolutely continuous with respect to — and write — if for every measurable set for which . It still essentially says that is small whenever is small, but here we describe “smallness” of by itself, while we describe “smallness” of by its total variation .

This situation is apparently asymmetric, but only apparently; If and are signed measures, then the conditions

are equivalent. Indeed, if is a Hahn decomposition with respect to then whenever we have both

Thus if the first condition holds we find

and the second condition must hold as well. If the second condition holds we use the definition

to show that the third must hold. And if the third holds, then we use the inequality

to show that the first must hold.

Now, just because smallness in can be equivalently expressed in terms of its total variation does *not* mean that smallness in can be equivalently expressed in terms of the signed measure itself. Indeed, consider the following two functions on the unit interval with Lebesgue measure :

and define to be the indefinite integral of . We can tell that the total variation is the Lebegue measure itself, since . Thus if then we can easily calculate

and so . However, it is *not* true that for every measurable with . Indeed, , and yet we calculate

By the way: it’s tempting to say that this integral is actually equal to , but remember that we only really know how to calculate integrals by taking limits of integrals of simple functions, and that’s a bit more cumbersome than we really want to get into right now.

One first quick result about absolute continuity: if and are any two measures, then . Indeed, if then by the positivity of measures we must have both and , the latter of which shows the absolute continuity we’re after.

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