The Unapologetic Mathematician

Mathematics for the interested outsider

A Family of Nontrivial Homology Classes (part 1)

We want to exhibit a family of closed n-forms that aren’t exact, albeit not all on the same space. In fact, there forms will provide models for every possible way a nontrivial homology class can arise.

For each n, we consider the space \mathbb{R}^{n+1}\setminus\{0\} consisting of the normal n+1-dimensional real affine space with the origin removed. Key to our approach will be the fact that we have a “retract” — a subspace \iota:U\hookrightarrow X along with a “retraction mapping” \pi:X\to U such that \pi\circ\iota=1_U. That is, the retraction mapping sends every point in X to some point in U, and the points that were in U to begin with stay exactly where they are. Explicitly in this case, the “punctured” n+1-dimensional space retracts onto the n-dimensional sphere by the mapping p\mapsto\frac{p}{\lvert p\rvert}, which indeed is the identity on the unit sphere \lvert p\rvert=1.

Now, in this space we take the position vector field P(p), which we define by taking the canonical identification \mathcal{I}_p:\mathbb{R}^{n+1}\to\mathcal{T}_p\mathbb{R}^{n+1} and applying it to the vector p itself: P(p)=\mathcal{I}_pp. We also take the canonical volume form du^0\wedge\dots\wedge du^n, and we use the interior product to define the n-form \hat{\omega}=\iota_P(du^0\wedge\dots\wedge du^n).

Geometrically, the volume form measures n+1-dimensional volume near any given point p. Applying the interior product with P is like rewriting the volume form in terms of a different basis so that P(p) is the first vector in the new basis and all the other vectors are perpendicular to that one, then peeling off the first term in the wedge. That is, \hat{\omega} measures n-dimensional volume in the space perpendicular to p — tangent to the sphere of radius \lvert p\rvert at the point p.

Next we restrict this form to S^n, and we pull the result back to all of \mathbb{R}^{n+1} along the retraction mapping \pi:\mathbb{R}^{n+1}\to S^n, ending up with the form \omega. I say that the net effect is that \omega=\frac{1}{\lvert p\rvert^n}\hat{\omega}, but the proof will have to wait. Still, the form \omega is the one we’re looking for.

About these ads

December 20, 2011 - Posted by | Differential Topology, Topology

3 Comments »

  1. [...] continue investigating the differential forms we defined last time. Recall that we started with the position vector field and use the interior product to produce the [...]

    Pingback by A Family of Nontrivial Homology Classes (part 2) « The Unapologetic Mathematician | December 20, 2011 | Reply

  2. [...] must now show that the forms we’ve defined are closed, and thus that they indeed will define homology classes. That is, . We must also show [...]

    Pingback by A Family of Nontrivial Homology Classes (part 3) « The Unapologetic Mathematician | December 27, 2011 | Reply

  3. [...] you remember our nontrivial homology classes, this is closely related to the one we built on — the case where . In that case we got a [...]

    Pingback by Gauss’ Law « The Unapologetic Mathematician | January 11, 2012 | Reply


Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

Follow

Get every new post delivered to your Inbox.

Join 392 other followers

%d bloggers like this: