Functoriality of the Derivative
We’ve said that the tangent bundle construction is a functor with the derivative as the action on morphisms. But we haven’t actually verified that it obeys the conditions of functoriality.
First off, if is the identity map on a smooth manifold
, then
should be the identity map between the tangent bundles. That is, at each point
we should have
the identity map on this vector space. And indeed, if we let
be any coordinate patch around
we know that the matrix of
with respect to these local coordinates is the Jacobian of the coordinate function
. But this Jacobian is clearly the identity matrix, proving our claim.
More importantly, if and
are two smooth maps, then their composition
is also smooth. Given a point
we can define the derivatives
,
, and
. I say that
. And since this holds at every point we can write
, proving functoriality.
So, let’s take a vector and see what happens. Taking a test function
we calculate
And so , just as we claimed.
We should note, here, how this recalls the Newtonian notation for the chain rule, where we wrote . Of course, multiplication is changed into composition of linear maps, but that little detail will be cleared up soon (if you don’t already see it).